College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Chapter 8 Review - Exercises - Page 641: 56

Answer

$1/9$

Work Step by Step

We add this step wise, $0.1+0.01=0.11$ $0.11+0.001 = 0.111$ $0.111+0.0001 = 0.1111$ The patern shows us the answer is is $.111111...$ That can be calculated with the infinity sum of a geometric series formula, $S_n = \frac{a}{1-r}$ Where $a$ is the first term and $r$ is the common ratio. $0.01/0.1 = 0.1$ The first term is $0.1$ $$S_n = \frac{0.1}{1-0.1} = 1/10* 10/9 = 1/9$$
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