Answer
$\frac{4(1+2x)}{x^{2/3}}$
Work Step by Step
$4x^{-2/3}+8x^{1/3}$
Take out common factor,
$4x^{-2/3}+8x^{1/3} = 4(x^{-2/3}+2x^{1/3})$
The greatest common factor is $x$ with the smaller exponent in the two terms. Thus the greatest common factor is $(x)^{-2/3}$
Express each term as the product of greatest common factor and its other factor.
$= 4(x^{-2/3}+2x^{1/3})$
$= 4(x^{-2/3}+2x.x^{-2/3})$ $[x . x^{-2/3} = x^{1-2/3} = x^{1/3}]$
Factor out the Greatest common factor.
$= 4x^{-2/3}(1+2x)$
$= \frac{4(1+2x)}{x^{2/3}} $ $[a^{-1/m} = \frac{1}{a^{1/m}}]$
