## College Algebra (6th Edition)

Published by Pearson

# Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.5: 91

#### Answer

$(2x)(x+6+2a)(x+6-2a)$

#### Work Step by Step

$2x^{3}-8a^{2}x+24x^{2}+72x$ Rearrange the terms to match the proper order. $=2x^{3}+24x^{2}+72x-8a^{2}x$ Factor out the common factor $2x$ from the expression. $=2x(x^{2}+12x+36-4a^{2})$ Group the first three terms. This is the perfect square trinomial. $=2x((x^{2}+12x+36)-4a^{2})$ The formula for it can be used here is $A^{2}+ 2.A.B+B^{2} =(A+B)^{2}$ Using the formula, factor the perfect square trinomial. $[x^{2}+2.x.6+6^{2}= (x+6) ^{2}$ $x^{2}+12x+36= (x+6) ^{2}]$ $=2x((x+6) ^{2}-4a^{2})$ $=2x((x+6) ^{2}-(2a)^{2})$ Factor the difference of squares. The factors are the sum and difference of the expressions being squared. Using the formula $[(a^{2}-b^{2}) = (a+b)(a-b)]$ $=(2x)(x+6+2a)(x+6-2a)$

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