## College Algebra (6th Edition)

a. $0.36x$ b. No, 36% of its original price
a. $(x-0.4x)-0.4(x-0.4x)$ Factor out $(x-0.4x)$ $= (x-0.4x)(1-0.4)$ Factor out $x$ from $(x-0.4x)$ $= x(1-0.4)(1-0.4)$ $= x(1-0.4)^{2}$ $= x(0.6)^{2}$ $=(0.36) x$ b. From part (a), sale price of the computer is $=(0.36) x$ $=(36/100 ) x$ where x is the original price Sale price of the computer is 36 % of original price.