College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.5 - Page 75: 116


a. $0.49x$ b. No, 49% of its original price

Work Step by Step

a. $(x-0.3x)-0.3(x-0.3x)$ Factor out $(x-0.3x)$ $ = (x-0.3x)(1-0.3)$ Factor out $x $ from $ (x-0.3x)$ $ = x(1-0.3)(1-0.3)$ $ = x(1-0.3)^{2}$ $ = x(0.7)^{2}$ $ =(0.49) x$ b. From part (a), sale price of the television is $ (0.49) x$ $ =(49/100 ) x$ where x is the original price So. the television store is selling at 49% of original price.
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