College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.5 - Page 75: 112

Answer

$(x+y)^{2}(x+y+10)(x+y-10)$

Work Step by Step

$(x+y)^{4}- 100(x+y)^{2}$ Takeout common factor $(x+y)^{2}$ $=(x+y)^{2}((x+y)^{2}-100)$ $=(x+y)^{2}((x+y)^{2}-10^{2})$ Use the formula $[(a^{2}-b^{2}) = (a+b)(a-b)]$ $=(x+y)^{2}((x+y)+10)((x+y)-10)$ $=(x+y)^{2}(x+y+10)(x+y-10)$
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