College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.5 - Page 75: 104

Answer

(x-1) (2x + 1) (6x - 5)

Work Step by Step

12$x^{2}$(x-1) - 4x(x-1) - 5(x-1) Take (x-1) common from given expression (x-1) (12$x^{2}$ - 4x - 5) do factor of (12$x^{2}$ - 4x - 5) (x-1) (12$x^{2}$ - 10x + 6x - 5) (x-1) (2x(6x - 5) +1(6x - 5)) (x-1) (2x + 1) (6x - 5)
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