Answer
$\frac{1}{3}\log_3x-4$
Work Step by Step
Use the following logarithmic formulas to expand the logarithm:
$\log(\frac{A}{B})=\log A-\log B$
$\log x^{n}=n\times\log x$
$\log_3(\frac{\sqrt[3] x}{81})$
$\log_3x^\frac{1}{3}-\log_381$
$\frac{1}{3}\log_3x-4$
