## College Algebra (6th Edition)

$x=-10$
Change base $9$ on the right side to match base $3$ on the left side by making it $3^2$. Then apply the distributive property, cancel out the bases, and set the sides equal to each other. Then solve for $x$. $3^{x-2}=9^{x+4}$ $3^{x-2}=(3^2)^{x+4}$ $3^{x-2}=3^{2x+8}$ $x-2=2x+8$ $x=-10$