College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Test - Page 513: 11



Work Step by Step

Change base $9$ on the right side to match base $3$ on the left side by making it $3^2$. Then apply the distributive property, cancel out the bases, and set the sides equal to each other. Then solve for $x$. $3^{x-2}=9^{x+4}$ $3^{x-2}=(3^2)^{x+4}$ $3^{x-2}=3^{2x+8}$ $x-2=2x+8$ $x=-10$
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