College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Test - Page 513: 13

Answer

$x\approx277.26$

Work Step by Step

Divide by $400$ on both sides. Then use the natural log on both sides, and then solve for $x$. $400e^{0.005x}=1600$ $e^{0.005x}=4$ $\ln e^{0.005x}=\ln4$ $0.005x=\ln4$ $x=\frac{\ln4}{0.005}$ $x\approx277.26$
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