College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Test - Page 513: 19


$120$ decibels

Work Step by Step

Substitute $I$ with $10^{12}I_{0}$ in the given formula: $D=10\displaystyle \log\frac{10^{12}I_{0}}{I_{0}}=10\log 10^{12}$ $... $Basic Logarithmic Properties: $\log_{b}b^{x}=x$... $D=10\cdot 12=120$ decibels
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