Answer
$\displaystyle \frac{1}{2}=\log_{36}6$
Work Step by Step
Rewriting the radical in exponential form,
$\sqrt{36}=36^{1/2}$
we apply the
Definition of the logarithmic function:
For $x>0$ and $b>0, b\neq 1,$
$ y=\log_{b}x$ is equivalent to $b^{y}=x$.
In $36^{1/2}=b^{y},\qquad ($b=36, y=1/2), so
$36^{1/2}=6$ is equivalent to
$\displaystyle \frac{1}{2}=\log_{36}6$
