College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Test - Page 513: 17

Answer

$x=5$

Work Step by Step

Combine like terms. Then use the definition of the log function to rearrange the logarithm. Then factor the side with $x$ and solve. $-20$ is not part of the domain, so $5$ is the only answer. $\log x+\log(x+15)=2$ $\log x(x+15)=2$ $100=x^2+15x$ $x^2+15x-100=0$ $(x-5)(x+20)=0$ $x=5, x=-20$ $x=5$
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