College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Test - Page 513: 10



Work Step by Step

Use the following logarithmic formula to solve: $\log_ba=\frac{\log_a}{\log_b}$ $\log_{15}71 = \frac{\log_{71}}{\log_{15}} \approx 1.5741$
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