College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Test - Page 513: 16

Answer

$x\approx18.20$

Work Step by Step

Divide by $2$ on both sides. Then use the definition of the log function to rearrange the logarithm, and solve the equation for $x$. $2\ln(3x)=8$ $\ln(3x)=4$ $e^4=3x$ $x=\frac{e^4}{3}$ $x\approx18.20$
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