Answer
$f(x)=\sqrt[3] x$
$g(x)=7x+4$
Work Step by Step
$h(x)=\sqrt[3] {7x+4}$
For $$f(x)=\sqrt[3] x$$ and $$g(x)=7x+4,$$ we have $$(f\circ g)(x)=f(g(x))=\sqrt[3]{7x+4}=h(x).$$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 2 - Summary, Review, and Test - Review Exercises - Page 326: 84
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