Answer
a. $\sqrt {x+2}$
b. {$x|x \geq-2$}
Work Step by Step
$f(x)=\sqrt {x-1}$
$g(x)=x+3$
a.$(f\circ g)(x)=f(g(x))=\sqrt {x+3-1}=\sqrt {x+2}$
b. Domain of $f\circ g$ = {$x:x \geq-2$}
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 2 - Summary, Review, and Test - Review Exercises - Page 326: 82
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