Answer
a. $\sqrt {x+2}$
b. {$x|x \geq-2$}
Work Step by Step
$f(x)=\sqrt {x-1}$
$g(x)=x+3$
a.$(f\circ g)(x)=f(g(x))=\sqrt {x+3-1}=\sqrt {x+2}$
b. Domain of $f\circ g$ = {$x:x \geq-2$}
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