Answer
$f(x)=x^4$
$g(x)=x^2+2x-1$
Work Step by Step
$h(x)=(x^2+2x-1)^4$
For $$f(x)=x^4$$ and $$g(x)=x^2+2x-1,$$ we have $$(f\circ g)(x)=f(g(x))=(x^2+2x-1)^4=h(x).$$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 2 - Summary, Review, and Test - Review Exercises - Page 326: 83
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