College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Summary, Review, and Test - Review Exercises - Page 326: 102

Answer

(x+2$^2$+(y-4)$^2$=36

Work Step by Step

(h,k)=(-2,4) r=6 (x-h)$^2$+(y-k)$^2$=r$^2$ (x-(-2))$^2$+(y-(4))$^2$=6$^2$ (x+2)$^2$+(y-4)$^2$=36
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