Answer
a. $16x^2-8x+4$
b. $4x^2+11$
c. $124$
Work Step by Step
$f(x)=x^2+3$
$g(x)=4x-1$
a. $(f\circ g)(x)=f(g(x))=(4x-1)^2+3=16x^2-8x+4$
b. $(g\circ f)(x)=g(f(x))=4(x^2+3)-1=4x^2+11$
c. $(f\circ g)(3)=16(3)^2-8(3)+4=124$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 2 - Summary, Review, and Test - Review Exercises - Page 326: 79
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