College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Summary, Review, and Test - Review Exercises - Page 326: 101

Answer

x$^2$+y$^2$=9

Work Step by Step

(h,k)=(0,0) r=3 (x-h)$^2$+(y-k)$^2$=r$^2$ (x-0)$^2$+(y-0)$^2$=3$^2$ x$^2$+y$^2$=9
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