Answer
a. $f(g(x)=\sqrt {x+1}$
b. $g(f(x))=\sqrt x +1$
c. $f(g(3))=2$
Work Step by Step
$f(x)=\sqrt x$
$g(x)=x+1$
a. $(f\circ g)(x)=f(g(x)=\sqrt {x+1}$
b. $(g\circ f)(x)=g(f(x))=\sqrt x +1$
c. $(f\circ g)(3)=\sqrt{3+1}=2$
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