College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Summary, Review, and Test - Review Exercises - Page 326: 81

Answer

a. $\frac{1+x}{1-2x}$ b. $\left\{x|x \ne0, \frac{1}{2}\right\}$

Work Step by Step

$f(x)=\frac{x+1}{x-2}$ $g(x)=\frac{1}{x}$ a. $(f\circ g)(x)=f(g(x))=\frac{\frac{1}{x}+1}{\frac{1}{x}-2}=\frac{1+x}{1-2x}$ b. Domain of $f\circ g$ = {$x|x \ne0, \frac{1}{2}$}
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