Answer
a. $\frac{1+x}{1-2x}$
b. $\left\{x|x \ne0, \frac{1}{2}\right\}$
Work Step by Step
$f(x)=\frac{x+1}{x-2}$
$g(x)=\frac{1}{x}$
a. $(f\circ g)(x)=f(g(x))=\frac{\frac{1}{x}+1}{\frac{1}{x}-2}=\frac{1+x}{1-2x}$
b. Domain of $f\circ g$ = {$x|x \ne0, \frac{1}{2}$}