College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Review Exercises - Page 75: 76


$(7x-8)^2\left( 121-56x \right)$

Work Step by Step

Factoring the $GCF= (7x-8)^2 ,$ the given expression, $ (5-2x)(3)(7x-8)^2(7)+(7x-8)^3(-2) ,$ is equivalent to \begin{array}{l}\require{cancel} (7x-8)^2\left( \dfrac{(5-2x)(3)(7x-8)^2(7)}{(7x-8)^2}+\dfrac{(7x-8)^3(-2)}{(7x-8)^2} \right) \\\\= (7x-8)^2\left( (5-2x)(3)(7)+(7x-8)(-2) \right) \\\\= (7x-8)^2\left( 105-42x-14x+16 \right) \\\\= (7x-8)^2\left( 121-56x \right) .\end{array}
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