College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Review Exercises - Page 75: 75


$(3x-4)\left( 9x-34 \right)$

Work Step by Step

Factoring the $GCF= (3x-4) ,$ the given expression, $ (3x-4)^2+(x-5)(2)(3x-4)(3) ,$ is equivalent to \begin{array}{l}\require{cancel} (3x-4)\left( \dfrac{(3x-4)^2}{(3x-4)}+\dfrac{(x-5)(2)(3x-4)(3)}{(3x-4)} \right) \\\\= (3x-4)\left( 3x-4+(x-5)(2)(3) \right) \\\\= (3x-4)\left( 3x-4+6x-30 \right) \\\\= (3x-4)\left( 9x-34 \right) .\end{array}
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