College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Review Exercises: 74

Answer

$(5p+3q)(3m-2n)$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To factor the given expression, $ 15mp+9mq-10np-6nq ,$ use factoring by grouping. $\bf{\text{Solution Details:}}$ Grouping the first and second terms and the third and fourth terms, the given expression is equivalent to \begin{array}{l}\require{cancel} (15mp+9mq)-(10np+6nq) .\end{array} Factoring the $GCF$ in each group results to \begin{array}{l}\require{cancel} 3m(5p+3q)-2n(5p+3q) .\end{array} Factoring the $GCF= (5p+3q) $ of the entire expression above results to \begin{array}{l}\require{cancel} (5p+3q)(3m-2n) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.