College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Review Exercises: 48

Answer

$-\dfrac{19}{42}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Use the order of operations (PEMDAS - Parenthesis/Exponents, Multiplication/Division, Addition/Subtraction) to simplify the given expression, $ \dfrac{(-7)(-3)-(-2^3)(-5)}{(-2^2-2)(-1-6)} .$ $\bf{\text{Solution Details:}}$ Simplifying the exponents, the expression above becomes \begin{array}{l}\require{cancel} \dfrac{(-7)(-3)-(-8)(-5)}{(-4-2)(-1-6)} .\end{array} Simplifying the parenthesis, the expression above becomes \begin{array}{l}\require{cancel} \dfrac{(-7)(-3)-(-8)(-5)}{(-6)(-7)} .\end{array} Simplifying the product/quotient, the expression above becomes \begin{array}{l}\require{cancel} \dfrac{21-40}{42} .\end{array} Simplifying the sum/difference by making the fractions similar, the expression above becomes \begin{array}{l}\require{cancel} \dfrac{-19}{42} \\\\= -\dfrac{19}{42} .\end{array}
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