## College Algebra (11th Edition)

$(y+2)(x-1)$
$\bf{\text{Solution Outline:}}$ To factor the given expression, $xy+2x-y-2 ,$ use factoring by grouping. $\bf{\text{Solution Details:}}$ Grouping the first and second terms and the third and fourth terms, the given expression is equivalent to \begin{array}{l}\require{cancel} (xy+2x)-(y+2) .\end{array} Factoring the $GCF$ in each group results to \begin{array}{l}\require{cancel} x(y+2)-(y+2) .\end{array} Factoring the $GCF= (y+2)$ of the entire expression above results to \begin{array}{l}\require{cancel} (y+2)(x-1) .\end{array}