College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Review Exercises: 58

Answer

$16a^2-24ab+9b^2$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To simplify the given expression, $ (4a-3b)^2 ,$ use the special product on squaring binomials. $\bf{\text{Solution Details:}}$ Using the square of a binomial which is given by $(a+b)^2=a^2+2ab+b^2$ or by $(a-b)^2=a^2-2ab+b^2,$ the expression above is equivalent to \begin{array}{l}\require{cancel} (4a)^2-2(4a)(3b)+(3b)^2 \\\\= 16a^2-24ab+9b^2 .\end{array}
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