College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Review Exercises - Page 75: 52



Work Step by Step

Substituting $a=-1$, $b=-2$, and $c=4$, the given expression, $ \dfrac{3|b|-4|c|}{|ac|} ,$ evaluates to \begin{array}{l}\require{cancel} \dfrac{3|-2|-4|4|}{|(-1)(4)|} \\\\= \dfrac{3(2)-4(4)}{|-4|} \\\\= \dfrac{6-16}{4} \\\\= \dfrac{-10}{4} \\\\= \dfrac{\cancel{2}(-5)}{\cancel{2}(2)} \\\\= -\dfrac{5}{2} .\end{array}
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