College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises - Page 58: 95



Work Step by Step

Factor out $y^2$ to obtain: $=y^2(y^2+11y+30)$ RECALL: A trinomial of the form $x^2+bx+c$ can be factored if there are integers $d$ and $e$ such that $c=de$ and $b=d+e$. The trinomial's factored form will be: $x^2+bx+c=(x+d)(x+e)$ The trinomial above has $b=11$ and $c=30$. Note that $30=5(6)$ and $11= 5+6$. This means that $d=5$ and $e=6$ Thus, the factored form of the trinomial is: $(y+5)(y+6)$ Therefore, the completely factored form of the given expression is: $y^2(y+5)(y+6)$
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