Answer
$y^2(y+5)(y+6)$
Work Step by Step
Factor out $y^2$ to obtain:
$=y^2(y^2+11y+30)$
RECALL:
A trinomial of the form $x^2+bx+c$ can be factored if there are integers $d$ and $e$ such that $c=de$ and $b=d+e$.
The trinomial's factored form will be:
$x^2+bx+c=(x+d)(x+e)$
The trinomial above has $b=11$ and $c=30$.
Note that $30=5(6)$ and $11= 5+6$.
This means that $d=5$ and $e=6$
Thus, the factored form of the trinomial is:
$(y+5)(y+6)$
Therefore, the completely factored form of the given expression is:
$y^2(y+5)(y+6)$
