College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises: 94

Answer

$x(x-2)(x+10)$

Work Step by Step

Factor out $x$ to obtain: $=x(x^2+8x-20)$ RECALL: A trinomial of the form $x^2+bx+c$ can be factored if there are integers $d$ and $e$ such that $c=de$ and $b=d+e$. The trinomial's factored form will be: $x^2+bx+c=(x+d)(x+e)$ The trinomial above has $b=8$ and $c=-20$. Note that $-20=-2(10)$ and $8= (-2)+10$. This means that $d=-2$ and $e=10$ Thus, the factored form of the trinomial is: $(x-2)(x+10)$ Therefore, the completely factored form of the given expression is: $x(x-2)(x+10)$
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