Answer
$x(x-2)(x+10)$
Work Step by Step
Factor out $x$ to obtain:
$=x(x^2+8x-20)$
RECALL:
A trinomial of the form $x^2+bx+c$ can be factored if there are integers $d$ and $e$ such that $c=de$ and $b=d+e$.
The trinomial's factored form will be:
$x^2+bx+c=(x+d)(x+e)$
The trinomial above has $b=8$ and $c=-20$.
Note that $-20=-2(10)$ and $8= (-2)+10$.
This means that $d=-2$ and $e=10$
Thus, the factored form of the trinomial is:
$(x-2)(x+10)$
Therefore, the completely factored form of the given expression is:
$x(x-2)(x+10)$
