College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises: 118

Answer

$(x-1)(x-3)$

Work Step by Step

We use the distributive property to factor by grouping and obtain: $(x-1)^{2}-2(x-1)=(x-1)[(x-1)-2] =(x-1)(x-3)$
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