Answer
$(x-1)^{2}(x^{2}+x+1)^{2}$
Work Step by Step
We factor:
$x^{6}-2x^{3}+1=(x^{3}-1)(x^3-1)=(x^3-1)^2
=[(x-1)(x^{2}+x+1)]^{2}
=(x-1)^{2}(x^{2}+x+1)^{2}$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises - Page 58: 103
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