College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises: 127

Answer

$2(3x+4)(9x+13)$

Work Step by Step

We factor by grouping to obtain: $2(3x+4)^{2}+(2x+3)* 2(3x+4)* 3 =2(3x+4)[(3x+4)^1+(2x+3)* 3] =2(3x+4)(3x+4+6x+9) =2(3x+4)(9x+13)$
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