College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises - Page 58: 131



Work Step by Step

We factor by grouping: $2(x+3)(x-2)^{3}+(x+3)^{2}* 3(x-2)^{2} =(x+3)(x-2)^{2}(2(x-2)^1+(x+3)^1* 3) =(x+3)(x-2)^{2}(2x-4+3x+9) =(x+3)(x-2)^{2}(5x+5) =5(x+3)(x-2)^{2}(x+1)$
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