# Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises - Page 58: 131

$5(x+3)(x-2)^{2}(x+1)$

#### Work Step by Step

We factor by grouping: $2(x+3)(x-2)^{3}+(x+3)^{2}* 3(x-2)^{2} =(x+3)(x-2)^{2}(2(x-2)^1+(x+3)^1* 3) =(x+3)(x-2)^{2}(2x-4+3x+9) =(x+3)(x-2)^{2}(5x+5) =5(x+3)(x-2)^{2}(x+1)$

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