College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises: 130

Answer

$x^{2}(32x-9)$

Work Step by Step

We factor by grouping to obtain: $3x^{2}(8x-3)+x^{3}* 8 =3x^{2}(8x-3)+8x*x^2 =x^{2}(3(8x-3)+8x) =x^{2}(24x-9+8x) =x^{2}(32x-9)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.