## College Algebra (10th Edition)

$(x+5)(3x+11)$
The trinomial $x^2+10x+25$ is a perfect square trinomial since the square of half of the middle term's coefficient, which is $(\frac{10}{2})^2=5^2$, is equal to the third term of the trinomial. This means that the factored form of the trinomial is $(x+5)^2$. Thus, the given expression is equivalent to: $=3(x+5)^2-4(x+5)$ Factor out $x+5$ to obtain: $=(x+5)[3(x+5)-4] \\=(x+5)(3x+15-4) \\=(x+5)(3x+11)$