College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises: 121

Answer

$(x+5)(3x+11)$

Work Step by Step

The trinomial $x^2+10x+25$ is a perfect square trinomial since the square of half of the middle term's coefficient, which is $(\frac{10}{2})^2=5^2$, is equal to the third term of the trinomial. This means that the factored form of the trinomial is $(x+5)^2$. Thus, the given expression is equivalent to: $=3(x+5)^2-4(x+5)$ Factor out $x+5$ to obtain: $=(x+5)[3(x+5)-4] \\=(x+5)(3x+15-4) \\=(x+5)(3x+11)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.