College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.6 - Logarithmic and Exponential Equations - 6.6 Assess Your Understanding - Page 466: 88

Answer

$x=4$

Work Step by Step

$\log_2x^{\log_2x}=4$ $(\log_2x)(\log_2x)=4$ $(\log_2x)^2=4$ $2\cdot\log_2x=4$ $\log_2x=\dfrac{4}{2}$ $\log_2x=2$ $x=2^2$ $x=4$ Verifying the answer: $\log_24^{\log_24}=4$ $2^2=4$ $4=4\checkmark$
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