Answer
$81$
Work Step by Step
We know that $k\log_{a^k}M=\log_aM$, hence $\log_{9}x+3\log_3x=2\log_{81}x+3\cdot4\log_{81}x=14\log_{81}x=14\\\log_{81}x=1\\\\x=81^1=81$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 6 - Section 6.6 - Logarithmic and Exponential Equations - 6.6 Assess Your Understanding - Page 466: 86
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