College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.6 - Logarithmic and Exponential Equations - 6.6 Assess Your Understanding - Page 466: 68

Answer

The solution set is $\{\log_{3}7\}$ or $\{1.771\}$.

Work Step by Step

... Substitute $t=3^{x}$ (t is positive) ... the equation becomes $t-14\displaystyle \cdot\frac{1}{t}-5=0 \quad $... multiply with t $t^{2}-14-5t=0 \quad $... rewrite, in order of powers $t^{2}-5t-14=0 \quad $... ... two factors of $-14$ whose sum is $-5$ ... are $-7$ and $+2$ $(t-7)(t+2)=0\quad \Rightarrow\quad t=7$ or $t=-2$ ... Since t must be positive, discard the $t=-2$ solution. ... Bring back x $t=7$ $3^{x}=7 \quad $...Apply$: \quad \log_{3}(...)$ $x=\log_{3}7\approx 1.771$ The solution set is $\{\log_{3}7\}$ or $\{1.771\}$
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