College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.6 - Logarithmic and Exponential Equations - 6.6 Assess Your Understanding - Page 466: 64

Answer

The solution set is $\{\log_{6}3\}$ or $\{0.613\}$

Work Step by Step

... $\quad 36^{x}=(6^{2})^{x}=(6^{x})^{2}$ ... Substitute $t=5^{x}$ (t is positive) ... the equation becomes $t^{2}-6t+9=0 \quad $...recognize a square of a difference $(t-3)^{2}=0$ $t=3 \quad $... bring back x $6^{x}=3 \quad $...Apply$: \quad \log_{6}(...)$ $x=\log_{6}3\approx 0.613$ The solution set is $\{\log_{6}3\}$ or $\{0.613\}$
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