Answer
$x=\displaystyle \frac{3}{2}$ or $x=-2$
Work Step by Step
We solve:
$(x-1)(2x+3)=3$
$2x^{2}+x-3=3$
$2x^{2}+x-3-3=0$
$2x^{2}+x-6=0$
$(2x-3)(x+2)=0$
$(2x-3)=0$ or $(x+2)=0$
$x=\displaystyle \frac{3}{2}$ or $x=-2$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Review Exercises - Page 145: 9
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