College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Review Exercises: 9


$x=\displaystyle \frac{3}{2}$ or $x=-2$

Work Step by Step

We solve: $(x-1)(2x+3)=3$ $2x^{2}+x-3=3$ $2x^{2}+x-3-3=0$ $2x^{2}+x-6=0$ $(2x-3)(x+2)=0$ $(2x-3)=0$ or $(x+2)=0$ $x=\displaystyle \frac{3}{2}$ or $x=-2$
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