Answer
$\displaystyle \frac{9}{10}-\frac{3}{10}i$
Work Step by Step
We simplify:
$\displaystyle \frac{3}{3+i}=\frac{3}{3+i}*\frac{3-i}{3-i}=\frac{3(3-i)}{(3+i)(3-i)}=\frac{9-3i}{9-3i+3i-i^{2}}=\frac{9-3i}{9--1}=\frac{9}{10}-\frac{3}{10}i$
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