College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Review Exercises: 37


$\displaystyle \frac{9}{10}-\frac{3}{10}i$

Work Step by Step

We simplify: $\displaystyle \frac{3}{3+i}=\frac{3}{3+i}*\frac{3-i}{3-i}=\frac{3(3-i)}{(3+i)(3-i)}=\frac{9-3i}{9-3i+3i-i^{2}}=\frac{9-3i}{9--1}=\frac{9}{10}-\frac{3}{10}i$
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