College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Review Exercises: 39



Work Step by Step

We simplify: $(2+3i)^{3}$ $=(2+3i)(2+3i)^{2}$ $=(2+3i)(4+12i+9i^{2})$ $=(2+3i)(-5+12i)$ $=-10-15i+24i+36i^{2}$ $=-46+9i$
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