## College Algebra (10th Edition)

$-46+9i$
We simplify: $(2+3i)^{3}$ $=(2+3i)(2+3i)^{2}$ $=(2+3i)(4+12i+9i^{2})$ $=(2+3i)(-5+12i)$ $=-10-15i+24i+36i^{2}$ $=-46+9i$