College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Review Exercises - Page 145: 16


$\displaystyle x=\frac{13}{2}$

Work Step by Step

We solve: $\sqrt[4]{2x+3}=2$ $(\sqrt[4]{2x+3})^{4}=2^{4}$ $2x+3=16$ $2x=16-3=13$ $\displaystyle x=\frac{13}{2}$
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