## College Algebra (10th Edition)

Published by Pearson

# Chapter 1 - Review Exercises - Page 145: 13

#### Answer

No real solutions.

#### Work Step by Step

We solve: $x(x+1)+2=0$ $x^{2}+x+2=0$ We solve using the quadratic formula ($a=1,\ b=1,\ c=2$): $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ $\displaystyle x=\frac{-1\pm\sqrt{(1)^{2}-4*1*2}}{2(1)}=\frac{-1\pm\sqrt{-7}}{2}$ However, we note that the discriminant is negative. Therefore, there are no real solutions.

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