## College Algebra (10th Edition)

We solve: $x(x+1)+2=0$ $x^{2}+x+2=0$ We solve using the quadratic formula ($a=1,\ b=1,\ c=2$): $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ $\displaystyle x=\frac{-1\pm\sqrt{(1)^{2}-4*1*2}}{2(1)}=\frac{-1\pm\sqrt{-7}}{2}$ However, we note that the discriminant is negative. Therefore, there are no real solutions.