College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Review Exercises: 41

Answer

$\displaystyle x=\frac{-1\pm\sqrt{17}}{4}$

Work Step by Step

We are given: $2x^{2}+x-2=0$ We solve using the quadratic formula ($a=2,\ b=1,\ c=-2$): $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ $\displaystyle x=\frac{-1\pm\sqrt{1^{2}-4*2*-2}}{2(2)}$ $\displaystyle x=\frac{-1\pm\sqrt{1+16}}{2(2)}$ $\displaystyle x=\frac{-1\pm\sqrt{17}}{2(2)}$ $\displaystyle x=\frac{-1\pm\sqrt{17}}{4}$
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