College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Review Exercises - Page 145: 22

Answer

$x=-\frac{9b}{5a}$ , $\frac{2b}{a}$

Work Step by Step

We simplify as follows: $10a^{2}x^{2}-2abx-36b^{2}=0$ $5a^{2}x^{2}-abx-18b^{2}=0$ $(5ax+9b)(ax-2b)$=0 CASE 1: $5ax+9b=0$ $5ax=-9b$ $x=-\frac{9b}{5a}$ CASE 2: $ax-2b=0$ $ax=2b$ $x=\frac{2b}{a}$ $x$ has two solutions: $-\frac{9b}{5a}$ and $\frac{2b}{a}$
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