Answer
$x=-\frac{9b}{5a}$ , $\frac{2b}{a}$
Work Step by Step
We simplify as follows:
$10a^{2}x^{2}-2abx-36b^{2}=0$
$5a^{2}x^{2}-abx-18b^{2}=0$
$(5ax+9b)(ax-2b)$=0
CASE 1:
$5ax+9b=0$
$5ax=-9b$
$x=-\frac{9b}{5a}$
CASE 2:
$ax-2b=0$
$ax=2b$
$x=\frac{2b}{a}$
$x$ has two solutions: $-\frac{9b}{5a}$ and $\frac{2b}{a}$