College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Review Exercises - Page 145: 21


$x=\frac{m}{1\pm n}$

Work Step by Step

$x^2+m^2=2mx+(nx)^2\\x^2+m^2-2mx=(nx)^2\\(x-m)^2=(nx)^2\\\sqrt{(x-m)^2}=sqrt{(n-x^2)}\\x-m=\pm(nx)\\x\pm nx=m\\x(1\pm n)=m\\x=\frac{m}{1\pm n}$
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